4y^4+2y^2=

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Solution for 4y^4+2y^2= equation:


Simplifying
4y4 + 2y2 = 0

Reorder the terms:
2y2 + 4y4 = 0

Solving
2y2 + 4y4 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '2y2'.
2y2(1 + 2y2) = 0

Ignore the factor 2.

Subproblem 1

Set the factor 'y2' equal to zero and attempt to solve: Simplifying y2 = 0 Solving y2 = 0 Move all terms containing y to the left, all other terms to the right. Simplifying y2 = 0 Take the square root of each side: y = {0}

Subproblem 2

Set the factor '(1 + 2y2)' equal to zero and attempt to solve: Simplifying 1 + 2y2 = 0 Solving 1 + 2y2 = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 2y2 = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 2y2 = 0 + -1 2y2 = 0 + -1 Combine like terms: 0 + -1 = -1 2y2 = -1 Divide each side by '2'. y2 = -0.5 Simplifying y2 = -0.5 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Solution

y = {0}

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